We obtain half-angle formulas from double angle formulas.
Both sin (2A) and cos (2A) are derived from the double angle formula for the cosine:
cos (2A) = cos2(A) − sin2(A) =
cos2(A) − (1 − cos2A) =
2cos2(A) − 1.
So, .
If we now replace A by (1/2)A, and take the square root
we get:
.
Similarly, we compute the sine half-angle:
cos (2A) = cos2(A) − sin2(A) =
1 − sin2(A) − sin2(A) = 1 −
2sin2(A).
So,
.
If we now replace A by (1/2)A, and take the square root,
we get:
.
For the tangent of the half-angle, tan
(2A),
we combine the identities for sine and cosine:
.
Again replacing A by (1/2)A, we get:
.
The following is a summary of the half-angle formulas:
Half-Angle Identities | ||
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Example: | Given that sin(A)= 3/5 and 90o < A < 180o, find sin(A/2). |
Solution: | First, notice that the formula for the sine of the half-angle involves
not sine, but cosine of the full angle. So we must first find the value of
cos(A). To do this we use the
Pythagorean
identity sin2(A) + cos2(A) = 1. In
this case, we find:
cos2(A) = 1 − sin2(A) = 1 − (3/5)2 = 1 − (9/25) = 16/25. The cosine itself will be plus or minus the square root of 16/25. Which is it? Well, to answer that we need to know in which quadrant A is. Since the angle A is between 90o and 180o, its sine is positive and its cosine is negative. So in this case, cos A = −4/5. We now apply this to the half-angle formula for sine:
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For the tangent of a half-angle there are additional identities; they have the advantage that the sign is decisive since there is no square root involved. They are:
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In the exercise that follows, you are asked to evaluate the sine or cosine of a half-angle given some information about the angle. Some of the answers in this exercise involve a radical under a radical (sometimes called a nested radical). Because of the difficulty in inputting such expressions, you are only to compare the answer you work out with that of the computer.
Sine and Cosine Half-Angle |
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In the exercise that follows, you are asked to evaluate the tangent of a half-angle given some information about the angle. Again, some of the answers in this exercise involve a radical under a radical and so you are only to compare the answer you work out with that of the computer.
Tangent Half-Angle |
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